Optimal. Leaf size=226 \[ -\frac {6 c^2 d^2 e^2}{\left (c d^2-a e^2\right )^5 (a e+c d x)}+\frac {3 c^2 d^2 e}{2 \left (c d^2-a e^2\right )^4 (a e+c d x)^2}-\frac {c^2 d^2}{3 \left (c d^2-a e^2\right )^3 (a e+c d x)^3}-\frac {10 c^2 d^2 e^3 \log (a e+c d x)}{\left (c d^2-a e^2\right )^6}+\frac {10 c^2 d^2 e^3 \log (d+e x)}{\left (c d^2-a e^2\right )^6}-\frac {4 c d e^3}{(d+e x) \left (c d^2-a e^2\right )^5}-\frac {e^3}{2 (d+e x)^2 \left (c d^2-a e^2\right )^4} \]
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Rubi [A] time = 0.21, antiderivative size = 226, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 33, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.061, Rules used = {626, 44} \begin {gather*} -\frac {6 c^2 d^2 e^2}{\left (c d^2-a e^2\right )^5 (a e+c d x)}+\frac {3 c^2 d^2 e}{2 \left (c d^2-a e^2\right )^4 (a e+c d x)^2}-\frac {c^2 d^2}{3 \left (c d^2-a e^2\right )^3 (a e+c d x)^3}-\frac {10 c^2 d^2 e^3 \log (a e+c d x)}{\left (c d^2-a e^2\right )^6}+\frac {10 c^2 d^2 e^3 \log (d+e x)}{\left (c d^2-a e^2\right )^6}-\frac {4 c d e^3}{(d+e x) \left (c d^2-a e^2\right )^5}-\frac {e^3}{2 (d+e x)^2 \left (c d^2-a e^2\right )^4} \end {gather*}
Antiderivative was successfully verified.
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Rule 44
Rule 626
Rubi steps
\begin {align*} \int \frac {d+e x}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^4} \, dx &=\int \frac {1}{(a e+c d x)^4 (d+e x)^3} \, dx\\ &=\int \left (\frac {c^3 d^3}{\left (c d^2-a e^2\right )^3 (a e+c d x)^4}-\frac {3 c^3 d^3 e}{\left (c d^2-a e^2\right )^4 (a e+c d x)^3}+\frac {6 c^3 d^3 e^2}{\left (c d^2-a e^2\right )^5 (a e+c d x)^2}-\frac {10 c^3 d^3 e^3}{\left (c d^2-a e^2\right )^6 (a e+c d x)}+\frac {e^4}{\left (c d^2-a e^2\right )^4 (d+e x)^3}+\frac {4 c d e^4}{\left (c d^2-a e^2\right )^5 (d+e x)^2}+\frac {10 c^2 d^2 e^4}{\left (c d^2-a e^2\right )^6 (d+e x)}\right ) \, dx\\ &=-\frac {c^2 d^2}{3 \left (c d^2-a e^2\right )^3 (a e+c d x)^3}+\frac {3 c^2 d^2 e}{2 \left (c d^2-a e^2\right )^4 (a e+c d x)^2}-\frac {6 c^2 d^2 e^2}{\left (c d^2-a e^2\right )^5 (a e+c d x)}-\frac {e^3}{2 \left (c d^2-a e^2\right )^4 (d+e x)^2}-\frac {4 c d e^3}{\left (c d^2-a e^2\right )^5 (d+e x)}-\frac {10 c^2 d^2 e^3 \log (a e+c d x)}{\left (c d^2-a e^2\right )^6}+\frac {10 c^2 d^2 e^3 \log (d+e x)}{\left (c d^2-a e^2\right )^6}\\ \end {align*}
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Mathematica [A] time = 0.19, size = 206, normalized size = 0.91 \begin {gather*} \frac {-60 c^2 d^2 e^3 \log (a e+c d x)+\frac {36 c^2 d^2 e^2 \left (a e^2-c d^2\right )}{a e+c d x}+\frac {9 c^2 d^2 e \left (c d^2-a e^2\right )^2}{(a e+c d x)^2}+\frac {2 c^2 d^2 \left (a e^2-c d^2\right )^3}{(a e+c d x)^3}+\frac {24 c d e^3 \left (a e^2-c d^2\right )}{d+e x}-\frac {3 e^3 \left (c d^2-a e^2\right )^2}{(d+e x)^2}+60 c^2 d^2 e^3 \log (d+e x)}{6 \left (c d^2-a e^2\right )^6} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {d+e x}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^4} \, dx \end {gather*}
Verification is not applicable to the result.
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fricas [B] time = 0.44, size = 1242, normalized size = 5.50
result too large to display
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.31, size = 586, normalized size = 2.59 \begin {gather*} -\frac {20 \, {\left (c^{3} d^{4} e^{3} - a c^{2} d^{2} e^{5}\right )} \arctan \left (\frac {2 \, c d x e + c d^{2} + a e^{2}}{\sqrt {-c^{2} d^{4} + 2 \, a c d^{2} e^{2} - a^{2} e^{4}}}\right )}{{\left (c^{6} d^{12} - 6 \, a c^{5} d^{10} e^{2} + 15 \, a^{2} c^{4} d^{8} e^{4} - 20 \, a^{3} c^{3} d^{6} e^{6} + 15 \, a^{4} c^{2} d^{4} e^{8} - 6 \, a^{5} c d^{2} e^{10} + a^{6} e^{12}\right )} \sqrt {-c^{2} d^{4} + 2 \, a c d^{2} e^{2} - a^{2} e^{4}}} - \frac {60 \, c^{5} d^{6} x^{5} e^{5} + 150 \, c^{5} d^{7} x^{4} e^{4} + 110 \, c^{5} d^{8} x^{3} e^{3} + 15 \, c^{5} d^{9} x^{2} e^{2} - 3 \, c^{5} d^{10} x e + 2 \, c^{5} d^{11} - 60 \, a c^{4} d^{4} x^{5} e^{7} + 270 \, a c^{4} d^{6} x^{3} e^{5} + 270 \, a c^{4} d^{7} x^{2} e^{4} + 45 \, a c^{4} d^{8} x e^{3} - 15 \, a c^{4} d^{9} e^{2} - 150 \, a^{2} c^{3} d^{3} x^{4} e^{8} - 270 \, a^{2} c^{3} d^{4} x^{3} e^{7} + 180 \, a^{2} c^{3} d^{6} x e^{5} + 60 \, a^{2} c^{3} d^{7} e^{4} - 110 \, a^{3} c^{2} d^{2} x^{3} e^{9} - 270 \, a^{3} c^{2} d^{3} x^{2} e^{8} - 180 \, a^{3} c^{2} d^{4} x e^{7} - 20 \, a^{3} c^{2} d^{5} e^{6} - 15 \, a^{4} c d x^{2} e^{10} - 45 \, a^{4} c d^{2} x e^{9} - 30 \, a^{4} c d^{3} e^{8} + 3 \, a^{5} x e^{11} + 3 \, a^{5} d e^{10}}{6 \, {\left (c^{6} d^{12} - 6 \, a c^{5} d^{10} e^{2} + 15 \, a^{2} c^{4} d^{8} e^{4} - 20 \, a^{3} c^{3} d^{6} e^{6} + 15 \, a^{4} c^{2} d^{4} e^{8} - 6 \, a^{5} c d^{2} e^{10} + a^{6} e^{12}\right )} {\left (c d x^{2} e + c d^{2} x + a x e^{2} + a d e\right )}^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.06, size = 221, normalized size = 0.98 \begin {gather*} \frac {10 c^{2} d^{2} e^{3} \ln \left (e x +d \right )}{\left (a \,e^{2}-c \,d^{2}\right )^{6}}-\frac {10 c^{2} d^{2} e^{3} \ln \left (c d x +a e \right )}{\left (a \,e^{2}-c \,d^{2}\right )^{6}}+\frac {6 c^{2} d^{2} e^{2}}{\left (a \,e^{2}-c \,d^{2}\right )^{5} \left (c d x +a e \right )}+\frac {3 c^{2} d^{2} e}{2 \left (a \,e^{2}-c \,d^{2}\right )^{4} \left (c d x +a e \right )^{2}}+\frac {4 c d \,e^{3}}{\left (a \,e^{2}-c \,d^{2}\right )^{5} \left (e x +d \right )}+\frac {c^{2} d^{2}}{3 \left (a \,e^{2}-c \,d^{2}\right )^{3} \left (c d x +a e \right )^{3}}-\frac {e^{3}}{2 \left (a \,e^{2}-c \,d^{2}\right )^{4} \left (e x +d \right )^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 1.68, size = 956, normalized size = 4.23 \begin {gather*} -\frac {10 \, c^{2} d^{2} e^{3} \log \left (c d x + a e\right )}{c^{6} d^{12} - 6 \, a c^{5} d^{10} e^{2} + 15 \, a^{2} c^{4} d^{8} e^{4} - 20 \, a^{3} c^{3} d^{6} e^{6} + 15 \, a^{4} c^{2} d^{4} e^{8} - 6 \, a^{5} c d^{2} e^{10} + a^{6} e^{12}} + \frac {10 \, c^{2} d^{2} e^{3} \log \left (e x + d\right )}{c^{6} d^{12} - 6 \, a c^{5} d^{10} e^{2} + 15 \, a^{2} c^{4} d^{8} e^{4} - 20 \, a^{3} c^{3} d^{6} e^{6} + 15 \, a^{4} c^{2} d^{4} e^{8} - 6 \, a^{5} c d^{2} e^{10} + a^{6} e^{12}} - \frac {60 \, c^{4} d^{4} e^{4} x^{4} + 2 \, c^{4} d^{8} - 13 \, a c^{3} d^{6} e^{2} + 47 \, a^{2} c^{2} d^{4} e^{4} + 27 \, a^{3} c d^{2} e^{6} - 3 \, a^{4} e^{8} + 30 \, {\left (3 \, c^{4} d^{5} e^{3} + 5 \, a c^{3} d^{3} e^{5}\right )} x^{3} + 10 \, {\left (2 \, c^{4} d^{6} e^{2} + 23 \, a c^{3} d^{4} e^{4} + 11 \, a^{2} c^{2} d^{2} e^{6}\right )} x^{2} - 5 \, {\left (c^{4} d^{7} e - 11 \, a c^{3} d^{5} e^{3} - 35 \, a^{2} c^{2} d^{3} e^{5} - 3 \, a^{3} c d e^{7}\right )} x}{6 \, {\left (a^{3} c^{5} d^{12} e^{3} - 5 \, a^{4} c^{4} d^{10} e^{5} + 10 \, a^{5} c^{3} d^{8} e^{7} - 10 \, a^{6} c^{2} d^{6} e^{9} + 5 \, a^{7} c d^{4} e^{11} - a^{8} d^{2} e^{13} + {\left (c^{8} d^{13} e^{2} - 5 \, a c^{7} d^{11} e^{4} + 10 \, a^{2} c^{6} d^{9} e^{6} - 10 \, a^{3} c^{5} d^{7} e^{8} + 5 \, a^{4} c^{4} d^{5} e^{10} - a^{5} c^{3} d^{3} e^{12}\right )} x^{5} + {\left (2 \, c^{8} d^{14} e - 7 \, a c^{7} d^{12} e^{3} + 5 \, a^{2} c^{6} d^{10} e^{5} + 10 \, a^{3} c^{5} d^{8} e^{7} - 20 \, a^{4} c^{4} d^{6} e^{9} + 13 \, a^{5} c^{3} d^{4} e^{11} - 3 \, a^{6} c^{2} d^{2} e^{13}\right )} x^{4} + {\left (c^{8} d^{15} + a c^{7} d^{13} e^{2} - 17 \, a^{2} c^{6} d^{11} e^{4} + 35 \, a^{3} c^{5} d^{9} e^{6} - 25 \, a^{4} c^{4} d^{7} e^{8} - a^{5} c^{3} d^{5} e^{10} + 9 \, a^{6} c^{2} d^{3} e^{12} - 3 \, a^{7} c d e^{14}\right )} x^{3} + {\left (3 \, a c^{7} d^{14} e - 9 \, a^{2} c^{6} d^{12} e^{3} + a^{3} c^{5} d^{10} e^{5} + 25 \, a^{4} c^{4} d^{8} e^{7} - 35 \, a^{5} c^{3} d^{6} e^{9} + 17 \, a^{6} c^{2} d^{4} e^{11} - a^{7} c d^{2} e^{13} - a^{8} e^{15}\right )} x^{2} + {\left (3 \, a^{2} c^{6} d^{13} e^{2} - 13 \, a^{3} c^{5} d^{11} e^{4} + 20 \, a^{4} c^{4} d^{9} e^{6} - 10 \, a^{5} c^{3} d^{7} e^{8} - 5 \, a^{6} c^{2} d^{5} e^{10} + 7 \, a^{7} c d^{3} e^{12} - 2 \, a^{8} d e^{14}\right )} x\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.15, size = 891, normalized size = 3.94 \begin {gather*} \frac {\frac {-3\,a^4\,e^8+27\,a^3\,c\,d^2\,e^6+47\,a^2\,c^2\,d^4\,e^4-13\,a\,c^3\,d^6\,e^2+2\,c^4\,d^8}{6\,\left (a^5\,e^{10}-5\,a^4\,c\,d^2\,e^8+10\,a^3\,c^2\,d^4\,e^6-10\,a^2\,c^3\,d^6\,e^4+5\,a\,c^4\,d^8\,e^2-c^5\,d^{10}\right )}+\frac {5\,e^2\,x^2\,\left (11\,a^2\,c^2\,d^2\,e^4+23\,a\,c^3\,d^4\,e^2+2\,c^4\,d^6\right )}{3\,\left (a^5\,e^{10}-5\,a^4\,c\,d^2\,e^8+10\,a^3\,c^2\,d^4\,e^6-10\,a^2\,c^3\,d^6\,e^4+5\,a\,c^4\,d^8\,e^2-c^5\,d^{10}\right )}+\frac {5\,d\,e\,x\,\left (3\,a^3\,c\,e^6+35\,a^2\,c^2\,d^2\,e^4+11\,a\,c^3\,d^4\,e^2-c^4\,d^6\right )}{6\,\left (a^5\,e^{10}-5\,a^4\,c\,d^2\,e^8+10\,a^3\,c^2\,d^4\,e^6-10\,a^2\,c^3\,d^6\,e^4+5\,a\,c^4\,d^8\,e^2-c^5\,d^{10}\right )}+\frac {5\,c\,e\,x^3\,\left (3\,c^3\,d^5\,e^2+5\,a\,c^2\,d^3\,e^4\right )}{a^5\,e^{10}-5\,a^4\,c\,d^2\,e^8+10\,a^3\,c^2\,d^4\,e^6-10\,a^2\,c^3\,d^6\,e^4+5\,a\,c^4\,d^8\,e^2-c^5\,d^{10}}+\frac {10\,c^4\,d^4\,e^4\,x^4}{a^5\,e^{10}-5\,a^4\,c\,d^2\,e^8+10\,a^3\,c^2\,d^4\,e^6-10\,a^2\,c^3\,d^6\,e^4+5\,a\,c^4\,d^8\,e^2-c^5\,d^{10}}}{x^2\,\left (a^3\,e^5+6\,a^2\,c\,d^2\,e^3+3\,a\,c^2\,d^4\,e\right )+x^3\,\left (3\,a^2\,c\,d\,e^4+6\,a\,c^2\,d^3\,e^2+c^3\,d^5\right )+x\,\left (2\,a^3\,d\,e^4+3\,c\,a^2\,d^3\,e^2\right )+x^4\,\left (2\,c^3\,d^4\,e+3\,a\,c^2\,d^2\,e^3\right )+a^3\,d^2\,e^3+c^3\,d^3\,e^2\,x^5}-\frac {20\,c^2\,d^2\,e^3\,\mathrm {atanh}\left (\frac {a^6\,e^{12}-4\,a^5\,c\,d^2\,e^{10}+5\,a^4\,c^2\,d^4\,e^8-5\,a^2\,c^4\,d^8\,e^4+4\,a\,c^5\,d^{10}\,e^2-c^6\,d^{12}}{{\left (a\,e^2-c\,d^2\right )}^6}+\frac {2\,c\,d\,e\,x\,\left (a^5\,e^{10}-5\,a^4\,c\,d^2\,e^8+10\,a^3\,c^2\,d^4\,e^6-10\,a^2\,c^3\,d^6\,e^4+5\,a\,c^4\,d^8\,e^2-c^5\,d^{10}\right )}{{\left (a\,e^2-c\,d^2\right )}^6}\right )}{{\left (a\,e^2-c\,d^2\right )}^6} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [B] time = 4.79, size = 1363, normalized size = 6.03
result too large to display
Verification of antiderivative is not currently implemented for this CAS.
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